[MINC-users] Compute overlap?

[Lisa F. Akiyama]

Hi Andrew and Alex,

Sorry about my delayed response.
Thank you for your assistance.
Just for clarification - the mincmath -and option calculates the volumes
shared by both input1 and inpu2?

Thank you.


Best,
Lisa


On Wed, Aug 31, 2011 at 7:17 AM, Andrew Janke <a.janke at gmail.com> wrote:

> >>   http://en.wikipedia.org/wiki/Dice%27s_coefficient
> >
> > Actually, it does not; the difference is that I use -add in the
> > mincmath call, so $stats[1] becomes n_intersection, and $stats[0] is
> > the sum of the relative complements. In other words, if the regions
> > are A and B, you calculate the denominator as
> >
> >  n(A) + n(B)
> >
> > which is equal to
> >
> >  2 * n(A ^ B) + n(A\B) + n(B\A)
>
> Ah, now I am with you....
>
> >> Although I am sure there are more things to compare with than just
> >> Dice's coefficient.
> >
> > That too - I'm always fascinated how many ways there are to turn the 4
> > values of a 2x2 confusion matrix into a number :) voldiff calculates
> > some but there are many more.
>
> Aye, I got half way through re-implementing the core of voldiff in
> minccmp for integer input volumes a while back but gave up with all
> the seemingly multiple contradictory definitions of how things should
> be done with a n x n confusion matrix across a variable number of
> files!  (you'll see a commented out -kappa option in there).
>
> All this talk of binary comparisons has got me all energised to finish
> it off again...
>
>
> a
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