[MINC-users] mincconcat question
Ghassan Hamarneh
minc-users@bic.mni.mcgill.ca
Wed, 19 Feb 2003 13:32:58 -0500 (EST)
Hi,
I tried:
$ mincconcat 0a.mnc 0b.mnc 0n.mnc -concat_dimension yspace
to concatenate two volumes 0a.mnc (384x183x256) to 0b.mnc (384x68x256) along
the second dimension and end up with 0n.mnc (384x[183+68]x256) volume, but I am
getting the message: Don't use an image dimension as a loop dimension.
What's the proper way to use this command in this case?
Thank you,
/Ghassan
--------
$ mincinfo 0a.mnc 0b.mnc
file: 0a.mnc
image: unsigned short 0 to 65535
image dimensions: xspace yspace zspace
dimension name length step start
-------------- ------ ---- -----
xspace 384 1 0
yspace 183 -1 -73
zspace 256 -1 0
file: 0b.mnc
image: unsigned short 0 to 65535
image dimensions: xspace yspace zspace
dimension name length step start
-------------- ------ ---- -----
xspace 384 1 0
yspace 68 -1 0
zspace 256 -1 0
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